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Re:Subtraction is not comparison by xmodem on Saturday December 27, 2014 @01:54AM (#8801917)
My C's a little rusty, but isn't the exact integer returned by the comparison undefined? Isn't is just defined as just zero or non-zero?

Therefore i would argue this is just as risky as the original solution, and that it's better to use the ternary operator

Re:Subtraction is not comparison by caf on Saturday December 27, 2014 @08:59PM (#8804837)
No, the relational operators (<, >, <= and >=) are defined to evaluate to either 0 or 1, and the result has type int.

The same is true of the equality operators (= and !=), the logical negation operator (!), and the logical boolean operators (&& and ||).

There are other C idioms based on this, like !!expr to squash a zero-or-non-zero expression down to zero-or-one.

Re:Subtraction is not comparison by mehrdada on Sunday December 28, 2014 @01:19AM (#8805507)
Regardless of the correctness of the code, if it's not obvious and you need to explain it, you probably should not write it (unless you have profile data that makes you do otherwise).

"Programs must be written for people to read, and only incidentally for machines to execute."

Re:Subtraction is not comparison by caf on Sunday December 28, 2014 @04:40AM (#8805865)
I think that particular example should be obvious to anyone whose C isn't "a little rusty".