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Re:Berkson's Paradox by sp332 on Wednesday September 03, 2014 @02:32PM (#8264519)
In this notation: P(A|B,C) what does the comma mean?
Re:Berkson's Paradox by tredontho on Wednesday September 03, 2014 @02:47PM (#8264580)
I think it's the intersection, so, "and".

P(A|B,C) is "Probability of A, given both B and C".

Re:Berkson's Paradox by spacehome on Wednesday September 03, 2014 @03:30PM (#8264825)
That's true, may be a slightly confusing way to interpret it, given that C = A∪B. In context I think it's better to read it as P(A|B), in the case that C occurs.
Re:Berkson's Paradox by theophrastus on Wednesday September 03, 2014 @04:11PM (#8265181)
wouldn't that be P((A|B)|C) ?

or even more precedence dubious: P(A|B|C) ?

Re:Berkson's Paradox by DrewAllyn on Wednesday September 03, 2014 @04:26PM (#8265266)
The "given" symbol should only appear once in any probability statement.
Re:Berkson's Paradox by spacehome on Wednesday September 03, 2014 @06:29PM (#8265809)
That's true from an objective, mathematical standpoint. But the paradox is really saying something about how humans perceive the statement, so different (mathematically equivalent) ways of framing the same thing can make a difference. It's a minor point.
Re:Berkson's Paradox by stepstep on Wednesday September 03, 2014 @03:59PM (#8265099)
Yeah it's tricky because in most programming languages, '|' has precedence over ',', but in math sometimes it's the opposite. That tripped me up too.
Re:Berkson's Paradox by Chinjut on Wednesday September 03, 2014 @04:44PM (#8265366)
In this context, the comma is as good as &.