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A comment on Mathematicians trace source of Rogers-Ramanujan identities, find algebraic gold. Parent comment

Re:Mathematicians trace source of Rogers-Ramanujan identitie... by nardi on Tuesday April 29, 2014 @07:30PM (#7670614)
The parent says, and I quote: "...then you get that the reals are uncountable only 'because' of transcendental numbers."

But this is untrue, is it not? Because even if you removed all of the real transcendentals, the real numbers would still be uncountable because of the irrationals.

(Edit: Or are the non-transcendental irrationals countable? I can see how that might be true?)

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Re:Mathematicians trace source of Rogers-Ramanujan identitie... by carstimon on Tuesday April 29, 2014 @07:49PM (#7670691)
Your edit is correct. Non-transcendentals are algebraic by definition, and the algebraic numbers are countable.
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[deleted]
Re:Mathematicians trace source of Rogers-Ramanujan identitie... by nardi on Tuesday April 29, 2014 @07:52PM (#7670705)
Ugh, embarrassingly obvious in retrospect. Thanks.
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