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Re:Unpythonic Python by placeybordeaux on Wednesday April 09, 2014 @03:21PM (#7561659)
Shorter and more pythonic, but not one per line:

' '.join(["FizzBuzz" if n%15==0 else "Fizz" if n%3==0 else "Buzz" if n%5==0 else str(n) for n in range(1,101)])

Re:Unpythonic Python by okwa on Wednesday April 09, 2014 @03:39PM (#7561789)
join on '\n' instead of ''. Problem solved.