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A comment on 0^0. Parent comment

Re:0^0 by j2kun on Wednesday April 02, 2014 @11:34PM (#7520782)
But what if you're in a context where you're not reasoning about continuous functions at all? Why would you have to be subject to reasoning that doesn't apply to your situation?
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Re:0^0 by einhverfr on Wednesday April 02, 2014 @11:43PM (#7520808)
That's actually an interesting point. And actually it occurs to me that even in continuous equations you have a problem:

Does it matter if we are talking 0^x or x^0?

I would think that in the context of 0^x, you'd have a constant function of 0, but x^0 you'd have a constant function of 1. These have different limits as x -> 0.

I think you have just convinced me that 0^0 is undefined.

Edit: Ouch. 0^x can't be defined for a negative x, so that doesn't work. I am back to siding with 1.

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