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A comment on Functional Programming 101 with Haskell. Parent comment

Re:Functional Programming 101 with Haskell by tdinkar on Friday January 24, 2014 @10:12AM (#7115200)
It's actually 9* (1 + 8 * (1 + 7 * (1 + 6 ..... + 1)))
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Re:Functional Programming 101 with Haskell by winstonsmith on Friday January 24, 2014 @01:21PM (#7116425)
= [9!e] - 1

(because your expression expands to 9 + 9(8) + 9(8)(7) + ... 9! = 9!(1+1/1 + 1/2! + ... 1/8!) = -1 + 9! e - (1/10 + 1/(10 11) + ...))

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