Re:Exact numeric nth derivatives
by jordigh on Thursday October 24, 2013 @03:14PM
(#6607248)
But knowing that sin' = cos is again begging the question, just rephrasing it back.
I think I get it, though. You can get away with simplifying intermediate steps of a differentiation computation if you only care about the value of the function at a single point.
I think I get it, though. You can get away with simplifying intermediate steps of a differentiation computation if you only care about the value of the function at a single point.