Because you (well, maybe not you, certainly not me, but perhaps some people) should be able to deduce the voltage from chemistry of the battery. So all LiIon LiMnO2 chemistry batteries have 3 V, LiFePO4 chemistry has 3.2 V.

Then you can just multiply the voltage by mAh and you have energy in mWh

The problem with this is two-fold. First - I shouldn't have to care about battery chemistry. Second - what if they're wired up in series [1]?

From personal experience, I've seen that laptop & mobile batteries list watt-hours as well. I'd prefer if that number was advertised instead.

[1]With two LiPo 3.7V 3Ah cells, you can have either 7.4V 3Ah or 3.7V 6Ah.

They rate them in volts and mAh, because depending on how quickly you take energy out of the battery you can end up with more or less total battery capacity (and while the mAh rating will change as well it won't change as much as the Wh rating).

@chrissmeuk, you've been hellbanned.

mAh is measured at 1V at 1 Ohm. So yes, your 8000mAh stores 3X as much as the 2650 mAh battery.

No, it's measured at the battery voltage (which is usually not 1V, and varies with discharge)

It's measured this way so you can most easily estimate runtime by putting an ammeter in series with the battery.

No way. I have no idea how mAh are measured in a lab, but they are certainly not in relation to 1V.

To get Wh, multiply by voltage. 2.6Ah * 1.2V = 3.1Wh. 8Ah * 4V (one cell is my assumption) = 32Wh.

The battery has 10x the capacity of a NiMH (that's the lower limit, it could have two cells but that seems a bit excessive for such a device).

Other than the battery discussion, Nokia devices running RT are about as interesting as the dirt on my shoes.