Functional Programming in 5 Minutes

Re:Functional Programming in 5 Minutes by callmecosmas on Sunday May 19, 2013 @04:00PM (#5734184)

You don't actually need the second lambda since all Haskell functions take one argument, so you can just do

  f = \x y -> x + y

and you'll have an implicit lambda before the y.

[ Parent | on HN ]

Re:Functional Programming in 5 Minutes by tel on Sunday May 19, 2013 @05:25PM (#5734447)

Yes, but that has an obvious lack of syntactic parallelism, one especially important when talking about currying since you might be tempted to relate that to the coffee script

    (X, y) -> x+y

It also has a subtly different performance characteristic in GHC, it turns out. Same semantics though.

[ Parent | on HN ]

Re:Functional Programming in 5 Minutes by alipang on Sunday May 19, 2013 @04:12PM (#5734225)

And of course it has operator segmenting so you can just write

    f = (+)

[ Parent | on HN ]

Re:Functional Programming in 5 Minutes by Peaker on Sunday May 19, 2013 @05:10PM (#5734406)

Or simply:

  f x y = x + y

[ Parent | on HN ]