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Re:Python’s lambda is broken by DavidSJ on Thursday April 09, 2009 @07:51PM (#555404)
I think you mean:

    (defun make-incrementers ()
        (let ((i 0))
            (cons (lambda () (incf i))
                  (lambda () (decf i)))))
Re:Python’s lambda is broken by jrockway on Thursday April 09, 2009 @08:23PM (#555451)
Yes, I did.