News for hackers. Stuff that matters.
Re:E-means: 10x faster k-means at equal loss by oofbey on Tuesday November 10, 2026 @01:19AM (#50436735)
There isn’t a well defined correct or ideal answer. It depends on what you’re doing with the clusters. Sometimes the raw data are too numerous to properly deal with and you just want a smaller set of points to reason about. In that case pick the number of points that are convenient to reason about. Sometimes you have a fixed budget for the cluster representation and that defines k. Sometimes just pick sqrt(N) so the average cluster size is k.

There are no comments on this comment yet.