Yeah, sorry, I'm mistaken. If one color is more probable than the other, you can win more by guessing odd rather than even, but you'd have to know the distribution. If you got 51 red hats every time, for example, you'd never win making even hats.

For this to work, however, you'd have to know the exact expected probability of each hat (and if it was even or odd), which is improbable.