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A comment on Fizz Buzz codegolf challenge in 15 languages. Parent comment

Re:Fizz Buzz codegolf challenge in 15 languages by glomph on Friday December 14, 2012 @02:11PM (#4922642)
OK I cheated and used google and found (60 chars):

  for i in range(1,101):print'FizzBuzz'[i*i%3*4:8--i**4%5]or i
Pastebin of my explanation: http://pastebin.com/raw.php?i=00Db30FF

EDIT: ugh, sometimes I hate markdown, moved post to pastebin.

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Re:Fizz Buzz codegolf challenge in 15 languages by GregBuchholz on Friday December 14, 2012 @07:21PM (#4924049)
Awesomely ingenious use of math above. 59 if newlines count as 1.

    i=1
    while i<101:print'FizzBuzz'[i*i%3*4:8--i**4%5]or i;i+=1
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Re:Fizz Buzz codegolf challenge in 15 languages by twiceaday on Sunday December 16, 2012 @10:48PM (#4930740)
Much simpler solution in 59 chars

  n=1
  while n<101:print'Fizz'*(n%3<1)+'Buzz'*(n%5<1)or n;n+=1
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Re:Fizz Buzz codegolf challenge in 15 languages by twiceaday on Tuesday December 18, 2012 @07:26PM (#4940545)
I came up with a shorter way to write the first index!

  n%-3&4
unbelievably it works
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Re:Fizz Buzz codegolf challenge in 15 languages by glomph on Monday December 24, 2012 @09:47AM (#4962938)
haha, clever!
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Re:Fizz Buzz codegolf challenge in 15 languages by glomph on Saturday December 15, 2012 @07:49AM (#4925212)
Should have been empty string f[4:4]
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