> Rust cannot take a const function and evaluate that into the argument of a const generic

Assuming I'm interpreting what you're saying here correctly, this seems wrong? For example, this compiles [0]:

    const fn foo(n: usize) -> usize {
        n + 1
    }

    fn bar<const N: usize>() -> usize {
        N + 1
    }

    pub fn baz() -> usize {
        bar::<{foo(0)}>()
    }

In any case, I'm a little confused how this is relevant to what I said?

[0]: https://rust.godbolt.org/z/rrE1Wrx36