Show HN: G=(hbar*c*2*(1+alpha/3)^2)/(m_p^2*4^64) ≈ 6.6742439706e-11 (8 ppm)

Re:Show HN: G=(hbar*c*2*(1+alpha/3)^2)/(m_p^2*4^64) ≈ 6.6742... by albert_roca on Tuesday December 23, 2025 @08:23AM (#46365136)

This is moving the goalposts, but ok. The model matches the international standard of CODATA 2022 to 0.005 ppm. If and when this value is updated, the prediction can be re-evaluated. Until then, I stick to the standard.

[ Parent | on HN ]

Re:Show HN: G=(hbar*c*2*(1+alpha/3)^2)/(m_p^2*4^64) ≈ 6.6742... by fatbrowndog on Tuesday December 23, 2025 @05:04PM (#46370016)

hi, the formula should allow both.

you have an integral and order^ power.

[ Parent | on HN ]