> every x in Q is in R but there exists at least one x in R not in Q, and no amount of correspondence shenanigans can get around that so |R|>|Q|.
This also applies to evens and naturals: evens are a strict subset of naturals and there exists naturals which are not evens.
A counter example in the reals is (0,1) and R have the same cardinality, despite there being real numbers not in the interval (0,1).
You have the fact incorrect: for infinite sets, all B being a strict subset of A shows is that |A| >= |B|.
However, while I can pair every rational number up with a real number, if I try to go the other way I find there is no rational number to pair with some (actually infinitely many) real numbers. I picked one, e, to show this. So the real numbers must be strictly larger than the rationals. Because the rationals are a strict subset of the reals it’s simpler than the Even/odd natural numbers because you don’t need the correspondence- every x in Q is in R but there exists at least one x in R not in Q, and no amount of correspondence shenanigans can get around that so |R|>|Q|.