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Re:C++26: A Placeholder with No Name by ogoffart on Saturday January 11, 2025 @01:16PM (#42667785)
Even without auto you have the problem.

    return foo().bar();
No `auto` and you still don't know the return type of foo. And knowing the type might not be the only reason you'd want an IDE anyway. What is `foo()` doing? I want to be able to easily jump to the definition of that function to verify that the assumption taken by the calling function are correct.

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