push 1
pop rax
pop rdi
You can't push a value once and pop it twice, that's not how a stack works! You're popping something else off the stack. So why does this even work?Linux passes your program arguments on the stack, with argc on top. So when you don't pass any arguments, argc just HAPPENS to be 1. Which you then pop into rdi. Gross!
With that fixed, is there any reason not to use push here?
push 1 ; 6A 01 (2 bytes)
pop rdi ; 5F (1 byte)
is longer than a simple: mov edi, eax ; 89 C7 (2 bytes)But even if it was 32 bit, then we would't have to copy a 1, since the syscall number for sys_write would be 4 instead of 1.
I get the same total size with both variants in 64 bit mode.
push 1
pop rax
mov rdi, rax
Assembling to 48 89 C7 (3 bytes)seems to be same in size as
push 1
pop rax
push 1
pop rdi
Assembling to 6A 01 5F (3 bytes)The default operand size in 64-bit mode is, for most instructions, still 32 bits. So `mov edi, eax` encodes the same in 32- and 64-bit mode.
For `mov rdi, rax` you need an extra REX prefix byte [1], that's the 48 you're seeing above, but you don't need it here.
[1] https://wiki.osdev.org/X86-64_Instruction_Encoding#REX_prefi...
I noticed that I then could also shave of one byte more by using lea esi, [rel msg] instead of lea rsi, [rel msg].
However, using the stack-based instructions as xpasky hinted at:
I get down to 159 bytes! I updated the article to reflect that