Build as many words as possible from the given letters

Re:Build as many words as possible from the given letters by genezeta on Monday September 02, 2024 @07:32AM (#41424491)

Given that you so generously keep the dictionary there, one can just open the console and paste:

    words.filter((word) => word.split('').every((letter) => "egtdrnq"].indexOf(letter) !== -1) && word.indexOf('d') !== -1 && word.length>3)

But, of course, that spoils the fun :)

[ Parent | on HN ]

Re:Build as many words as possible from the given letters by genezeta on Tuesday September 03, 2024 @05:29AM (#41433008)

More generally (speed may need to be adjusted):

  var letters = $$('.hex').map((x)=>x.textContent.toLowerCase()).join('');
  var obLetter = $('.hex.yellow').textContent.toLowerCase();
  var sol = words.filter((word) => word.split('').every((letter) => letters.indexOf(letter) !== -1) && word.indexOf(obLetter) !== -1 && word.length>3);

  let tick = 0;
  let nextWord = ()=>{
    $('#textInput').value=sol[tick].toUpperCase();
    $('.enter-button').click();
    tick++;
    if(tick<sol.length) setTimeout(nextWord, 50);
  };
  setTimeout(nextWord, 30);

[ Parent | on HN ]