Re:Non-computability of solutions of certain equations on di...
by lisper on Sunday August 04, 2024 @11:58AM
(#41154336)
Thanks!
I think you don't even need arctan for this. Just put one of Myhill's "bumps" at x=0 and shrink it down. That function approaches f(x)=0 for all x but its derivative at x=0 remains 1.
By contrast, the integration operator is computable. Why? Because a piece of code that defines a function f over the real numbers can be generalised to interval numbers (see "interval arithmetic") -- it then follows that the upper and lower Darboux sums are both computable. QED
[edit] Changed oo to 0.