Re:Non-computability of solutions of certain equations on di...
by bubblyworld on Sunday August 04, 2024 @06:15AM
(#41152448)
Equality over computable reals is not decidable, so I don't think you've actually defined a computable function here. The issue is much more subtle than that.
Like this
f(0) = 1
f(x!=0) = 0
It's more of a mathematical trick than anything else, it's not a "natural function" let's put it this way