Obviously in userspace it would only crash the running program and not the entire operating system? It's a significant difference.
All of the service interruptions would have been just "computer temporarily not protected by crowdstrike agent". Not the same thing at all.
Re:No More Blue Fridays
by CodeWriter23 on Monday July 22, 2024 @10:14AM
(#41034646)
> It's a significant difference.
When various apps running the world are crashing, unable to execute because malware protection is failing, there is no difference.
_No_ difference oversells it, IMO -- the fact that the entire OS crashed is what made fixing the bug so arduous, since it required in-person intervention. To be sure, running the code in userspace would still cause unacceptable service interruptions, but the fix could be applied remotely.
> Obviously in userspace it would only crash the running program and not the entire operating system? It's a significant difference.
Significant and often far worse. It would leave the machine running unprotected.
At Ring 3 it would crash an app, not the entire OS.
Yes, the kernel is fine and is not to blame. But running basically a rootkit controlled by a third party indeed is to blame.
Re:No More Blue Fridays
by CodeWriter23 on Monday July 22, 2024 @10:13AM
(#41034624)
> At Ring 3 it would crash an app, not the entire OS.
That's still an outage for those key systems.
It is an outage for the monitoring system, not the system that it monitors.
Re:No More Blue Fridays
by CodeWriter23 on Monday July 22, 2024 @07:07PM
(#41040773)
I think a reasonable protocol is to stop using any apps when your cyber protection crashes. Why have that suite at all otherwise?
I agree for some systems. For others, stopping the system has bigger consequences than not having cyber protection for a few hours because of a bug that’ll get fixed. For example, hospitals, or possibly Delta Airlines.
I take issue with that. Kernel programming was not to blame; looking up addresses from a file and accessing those memory locations without any validation is. The same technique would yield the same result at any Ring.