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Re:Structuralism as a Philosophy of Mathematics by auggierose on Sunday April 07, 2024 @07:16PM (#39964788)
So what? We can still only prove those theorems that also hold in all of those other structures that we don't mean, but sweep up anyway.
Re:Structuralism as a Philosophy of Mathematics by cubefox on Monday April 08, 2024 @02:31AM (#39966815)
It's not clear what "the structure we mean" means without a way of definitely identifying it in our mind. Categorical axioms just make this explicit.
Re:Structuralism as a Philosophy of Mathematics by auggierose on Monday April 08, 2024 @02:55AM (#39966947)
Yes, that's true. I think it is good to have a logic with a semantics which allows you to clearly say what the "standard models" are. For those models categoricity should be achievable. But at the same time it is also clear that there will always be other models, for which categoricity doesn't hold.
Re:Structuralism as a Philosophy of Mathematics by cubefox on Monday April 08, 2024 @09:20AM (#39969445)
Categoricity isn't a property of a model, it's a property of a set of axioms which only have "one model up to isomorphism", or one "structure" in the sense of structuralism.
Re:Structuralism as a Philosophy of Mathematics by auggierose on Monday April 08, 2024 @10:44PM (#39975828)
As commonly defined, you are right, but if you have the ability to select among your models, then you can use that to sharpen your notion of categoricity by considering only a certain class of models instead of all models.

You can say for example, categorical with respect to a certain cardinality of the model, that is you are only considering models of that cardinality.

And just like that, if your semantic allows it, you can also say categorical with respect to standard models. But for that you of course need a clear definition of what "standard" means. First-order logic doesn't provide such a clear definition.