Re:Kolmogorov Complexity and Compression Distance
by tromp on Sunday March 31, 2024 @04:14AM
(#39882420)
KC(x) is always finite for any finite x. What we can say instead is that KC is unbounded. I.e. there is no finite bound on the value of KC(x).
[ Parent
| on HN ]
There are no comments on this comment yet.