Re:Why is division so much more complex than other arithmeti...
by ridiculous_fish on Friday August 11, 2023 @04:02PM
(#37093298)
For flooring integer division with a bounded dividend and known constant, the idea is to multiply by a scaled reciprocal. For example with 32 bit division by 3, you might precompute 2^32 / 3, multiply by that, and then flooring-divide by 2*32 (right shift).
It gets tricky because 2^32/3 is not an integer, so you must round it. This introduces error; the idea is to show that the error is wiped out by the flooring divide. I did the monster math here:
It gets tricky because 2^32/3 is not an integer, so you must round it. This introduces error; the idea is to show that the error is wiped out by the flooring divide. I did the monster math here:
https://ridiculousfish.com/blog/posts/labor-of-division-epis...