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Re:Peter Norvig: Tweaking Bayes' Theorem by sbmassey on Monday March 12, 2012 @11:34AM (#3693883)
Iwwelewant Cowwection! Actual Bayes law is:

P(W|A) = P(A|W)P(W)/P(A)

Re:Peter Norvig: Tweaking Bayes' Theorem by bermanoid on Monday March 12, 2012 @11:40AM (#3693913)
If you're maximizing over all possible values of W, A never changes, which is why the /P(A) will usually be omitted from the function you're maximizing.

You're right, though, it shouldn't be written as P(W|A) in that case, that's misleading.

Re:Peter Norvig: Tweaking Bayes' Theorem by jshen on Monday March 12, 2012 @11:43AM (#3693925)
P(A) is the same for all candidates you are considering so you drop it.
Re:Peter Norvig: Tweaking Bayes' Theorem by tel on Monday March 12, 2012 @12:58PM (#3694321)
True, but I didn't feel like writing \propto