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Re:Sleeping Through the Technical Interview (2022) by xena on Friday July 07, 2023 @03:13PM (#36636911)
Depends on what you mean by "time". Going by algorithmic complexity time it's at least linear yes. Going by wall clock time (the more important one for interview code) it's constant time.
Re:Sleeping Through the Technical Interview (2022) by shimmy568 on Friday July 07, 2023 @03:31PM (#36637153)
The time to spawn the threads is just inconsequential compared to the time to wait for the threads to exit for small sizes of N. But by doubling the number of numbers to sort you do double the time (actual wall clock time) that it takes to spawn those threads. O(N + 10000000) is still O(N)

Not to mention for the OS to handle N threads would likely take some kind of non-linear time, at least N^2 if I had to take a shot in the dark. But I imagine it'd depend on the OS and how the hardware handles interrupts. Even if the thread is sleeping it still takes resources to schedule it

Re:Sleeping Through the Technical Interview (2022) by colanderman on Friday July 07, 2023 @03:58PM (#36637515)
Linux's CFS is O(log N) to insert; O(1) to switch tasks (N being number of threads). [1] So O(N log N) it seems.

[1] https://en.wikipedia.org/wiki/Completely_Fair_Scheduler#Algo...

Re:Sleeping Through the Technical Interview (2022) by upon_drumhead on Friday July 07, 2023 @03:26PM (#36637084)
I don’t understand how wall clock time is constant.

Sorting [5, 50] is faster wall time then [6, 60].

Re:Sleeping Through the Technical Interview (2022) by xena on Friday July 07, 2023 @03:27PM (#36637099)
The constant is the biggest number in the array
Re:Sleeping Through the Technical Interview (2022) by NotYourLawyer on Friday July 07, 2023 @03:33PM (#36637176)
If runtime depends on the input, it’s not constant time.
Re:Sleeping Through the Technical Interview (2022) by addaon on Friday July 07, 2023 @05:21PM (#36638474)
It's constant with regards to the length of the input array, which is the usual metric for sort algorithm performance. That is, d(runtime)/d(len(input)) can be constant, even though d(runtime)/d(max(input)) is not, if you assume that len(input) is independent from max(input) (which is inconsistent with input having uniformly distributed random members, which is probably the more common assumption).
Re:Sleeping Through the Technical Interview (2022) by recursive on Friday July 07, 2023 @06:51PM (#36639307)
It's constant with respect to the number of elements, just not the maximum magnitude of those elements.
Re:Sleeping Through the Technical Interview (2022) by upon_drumhead on Friday July 07, 2023 @07:05PM (#36639432)
I don't see how it is. Different, but the same number, of elements is a different time. There's no constant time between [0, 1] and [0, 10], both having two elements.
Re:Sleeping Through the Technical Interview (2022) by squeaky-clean on Friday July 07, 2023 @07:12PM (#36639478)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

is just as fast as

[9]

If you really want to make it strictly constant time, just append INT32_MAX to the end of the array before sorting, and then pop it after.

Re:Sleeping Through the Technical Interview (2022) by libealistand on Saturday July 08, 2023 @03:02AM (#36642047)
Oh yeah, because assumin maximum values in your domain doesn't move all algorithms into constant time and renders complexity theory void.
Re:Sleeping Through the Technical Interview (2022) by squeaky-clean on Saturday July 08, 2023 @08:47PM (#36650276)
It doesn't though. How would merge sort become constant time if you assume a maximum value? It's also a joke...
Re:Sleeping Through the Technical Interview (2022) by libealistand on Monday July 10, 2023 @02:05AM (#36662676)
The main "value" in the domain of sorting problems is the number of elements in your collection.

A subproblem also considers the elements to be integers, then they become another "value" domain. (But in general, sorting problems only need their elements to be comparable, not necessarily integers.)

Re:Sleeping Through the Technical Interview (2022) by saagarjha on Friday July 07, 2023 @09:46PM (#36640558)
It’s not constant; the algorithm runs in pseudo-polynomial time.
Re:Sleeping Through the Technical Interview (2022) by fenomas on Saturday July 08, 2023 @01:21AM (#36641565)
You're forgetting that complexity analysis deals with asymptotic behavior.

An algorithm that takes N inputs, does N operations, and then sleeps for 10 seconds is not constant time, because in the asymptotic case the N iterations will take longer than the sleep.