A trick to eliminate 2π (sometimes)

Re:A trick to eliminate 2π (sometimes) by scythe on Wednesday June 28, 2023 @02:02PM (#36510206)

If you're really slick about it, you even "fix" the Gaussian integral this way.

Let é = e^sqrt(2pi), déx = dx/sqrt(2pi), and we have

int_{R}(é^(int_0^x(t dét)) déx)

= int_{R}(e^(sqrt(2pi) x^2/(2 sqrt(2pi))) dx/sqrt(2pi))

= 1/sqrt(2pi) int_{R}(e^(x^2/2) dx)

= sqrt(2pi) / sqrt(2pi)

= 1

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Re:A trick to eliminate 2π (sometimes) by enriquto on Wednesday June 28, 2023 @03:01PM (#36511001)

> exp(sqrt(2pi))

Now, this is a number that I don't recall having seen before. The letter é seems strangely fitting for it

é = 12.2635111...

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