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Re:A Little Calculus by bg46z on Thursday May 04, 2023 @09:14PM (#35824196)
d/dx is not a fraction but an operation, dy/dx is a fraction
Re:A Little Calculus by xvedejas on Thursday May 04, 2023 @09:39PM (#35824330)
Is `dy/dx` ever distinct from `d/dx y`? Generally I've treated `df(x)/dx` as just another way to write the operator `d/dx` applied to `f(x)`, which I don't think of as a fraction.
Re:A Little Calculus by lupire on Thursday May 04, 2023 @11:17PM (#35824838)
dy/dt = dy/dx * dx/dt
Re:A Little Calculus by xvedejas on Friday May 05, 2023 @11:11PM (#35837596)
That's just the chain rule, right?

d/dt y(t) = ( d/dx y(x) )( d/dt x(t) )

Re:A Little Calculus by rtpg on Thursday May 04, 2023 @09:36PM (#35824311)
What series of operations can lead you to end up with dy/dx though? Like Integral{x^2){dx} is how you're introducing dx into a formula, but it's not like integration just works over division, so I'm a bit stuck on the construction phase
Re:A Little Calculus by lupire on Thursday May 04, 2023 @11:16PM (#35824832)
y = x^2

dy = 2x dx

dy/dx = 2x

Chain rule makes this not completely trivial formulation.