1.354e14 kg assuming the Death Star has a radius of 160 km. However there's conflicting information about the diameter of the Death Star (some say 120 km, others 160 km) and that's the diameter and not the radius.

So the Death Star would be considerably lighter than your friend's calculation.

My calculations give 3.385e13 kg assuming a radius of 80 km which yields a density of 1.578e-2 kg/m3 or 15.78 g/m3 which is way, way low. In fact it's much lower than the density of air.

Three possibilities: I made a mistake in my calculation, Google's gravity value for the Death Star is incorrect, we shouldn't expect consistency from a story George Lucas made up almost 40 years ago.

Wouldn't you assume the Death Star has artificial earth-normal gravity, just like all the spaceships? (Not to crash the geeky fun with geeky observations.)

I think it's that you made a mistake. How could the other possibilities be true!?

;)

Plus the Death Star was full of really dense stuff that was fuel or some ship

The Island on Lost, perhaps?

Yes, it's 4.815162, Lost numbers are 4 8 15 16 2[3 42].

Ahhh, right, that explains it.

However, while I haven't watched every episode of Lost I think it'd be a lot more noticeable if gravity there was 4.815162 times regular Earth gravity. Everybody would be crawling around, for starters.

yeah, though the numbers don't seem to be multiples or constants (except for the death star one), they seem to be metric accelerations

Oops, you're right, I hadn't checked.

That'd make island gravity roughly half of regular Earth gravity.

I always thought that was electromagnetic. Does The Island have impressive mass as well?