But you might be asking. “Why can’t I just assign the source variable directly to the destination variable?”

    int main() {
      char source[] = "Hello, world!";
      char* destination = source;
    
      strcpy(destination, source); // Copy the source string to the destination string
    
      printf("Source: %s\n", source);
      printf("Destination: %s\n", destination);
    
      return 0;
    }
    You can. It’s just that destination now becomes a char* and exists as a pointer to the source character array. If that isn’t what you want them this will almost certainly cause issues.