Re:Single-block collision for MD5
by 0x0 on Sunday January 29, 2012 @06:27PM
(#3526668)
Fair point. I just kind of assumed that any collision would require quite a lot of flipped bits, because usually just one flipped bit is enough to cause an "avalanche" of changes in the hash sum.
Would it be possible to find a collision where only one bit is flipped in the input?
Would it be possible to find a collision where only one bit is flipped in the input?