> It can't zip more than two per se, but you could zip the result of the first zip into a third and get ((item1, item2), item3). You could then map these if you wanted, to flatten them into a single tuple .map(|((item1, item2), item3)| (item1, item2, item3))

FWIW that's more or less what `itertools::izip!` does for you, it just chains `zip`s then "splats" them using a `map`.