Re:Cistercian Numerals
by MayeulC on Tuesday January 31, 2023 @07:31AM
(#34594259)
I'd make it binary-like, like another commenter said.
Change 3 to 2+1, 6 to 4+2.
8 takes the current 6, and 7 becomes 6+1, 9 becomes 8+1 (current 7). That also gives you hex digits to work with for free, each symbol could store up to FFFF.
It wouldn't change a lot, just removes the downstroke from 3.
Of course, 4 bits is an arbitrary choice, one could keep the current 5 bit/segments as well, but not much is needed to normalize it to 4 bits, which is interesting in itself.
Change 3 to 2+1, 6 to 4+2.
8 takes the current 6, and 7 becomes 6+1, 9 becomes 8+1 (current 7). That also gives you hex digits to work with for free, each symbol could store up to FFFF.
It wouldn't change a lot, just removes the downstroke from 3. Of course, 4 bits is an arbitrary choice, one could keep the current 5 bit/segments as well, but not much is needed to normalize it to 4 bits, which is interesting in itself.