Re:ᚣ the Rune Programming Language
by yccs27 on Sunday November 27, 2022 @11:39AM
(#33764224)
It all gets more complicated when you want to pass more than one secret parameter, or the function already returns a Secret - now you need a monad. The key feature seems to be that the code does not need 'map' or anything, the secrecy flag is propagated regardless.
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Re:ᚣ the Rune Programming Language
by grantjpowell on Sunday November 27, 2022 @12:01PM
(#33764430)
> now you need a Monad
"need a Monad" sounds scary but in practice it looks like this
impl<T> Secret<T> {
pub fn map<U>(&self, func: impl FnOnce(&T) -> U) -> Secret<U> {
Secret(func(&self.0))
}
pub fn flat_map<U>(&self, func: impl FnOnce(&T) -> Secret<U>) -> Secret<U> {
func(&self.0)
}
}
If you need an escape hatch for something more complicated, you could provide an api to that impl<T> Secret<T> {
pub unsafe fn reveal(&self) -> &T {
&self.0
}
}My point, which I didn’t express well there, was about the call side: How do you call
func(param1: A, param2: B) -> C
with both parameters being secrets (secret1: Secret<A>, secret2: Secret<B>)? In Rust, it‘s flat_map(secret1, |param1|
map(secret2, |param2|
func(param1, param2)
)
)
or with do_notation at least a bit cleaner do! {
param1 <- secret1;
param2 <- secret2;
Secret(func(param1, param2));
}
whereas Rune manages it with func(secret1, secret2)