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Re:How to rip audio CDs 2022 – with drive accuracy listing by extropy on Monday November 07, 2022 @03:58AM (#33503142)
The accuracy figures in TA are kinda low - 99.7 for the top one, averaging out at 98.5%.

Anyone has some idea what is this measuring?

Bit accuracy (way too low)? A full disk read 100% error free? The actual accuracy really depends on the quality of the disc, is this measured with a reference disc?

Re:How to rip audio CDs 2022 – with drive accuracy listing by kroeckx on Monday November 07, 2022 @04:27AM (#33503417)
This is based on submission to AccurateRip. As I understand it, it's how many tracks submitted by users owning that drive match the what AccurateRip considers the correct rip.
Re:How to rip audio CDs 2022 – with drive accuracy listing by TacticalCoder on Monday November 07, 2022 @07:52AM (#33505148)
> As I understand it, it's how many tracks submitted by users owning that drive match the what AccurateRip considers the correct rip.

Wait: I'm pretty sure that's not how it works at all. No matter the drive, there's only one correct rip. And two people won't, by coincidence, happen to read the same disc with the exact same error(s).

So when you rip and compare to the AccurateRip DB, you know you have the correct rip if it matches the one already in the DB.

I don't think AccurateRip "considers" rips correct not: to me it knows with 100% guarantee. Which is the entire selling point of the AccurateRip DB. And which is why it's called that way.

Re:How to rip audio CDs 2022 – with drive accuracy listing by gcbirzan on Monday November 07, 2022 @04:13AM (#33503291)
How many of the discs ripped were 100% error free, from what I understand it compares against a database of checksums, the one that has the most 'votes' is considered to be correct.
Re:How to rip audio CDs 2022 – with drive accuracy listing by rasz on Monday November 07, 2022 @05:08AM (#33503842)
Its a shit way of expressing data they collect. It means every single drive model had at least one owner try to rip badly scratched disk.