Re:A number that can't be calculated
by kotlin2 on Tuesday October 25, 2022 @04:10PM
(#33335519)
If you could inspect any Turing machine and devise a specific algorithm that determines if it halts, then you yourself would be an algorithm that solves the generic halting problem.
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no, because you can build an algorithm that fools the algorithm that solves the generic halting problem. I wrote a "proof" of that in my blog [1]
Exactly. So your claim that:
> So you can remove the ones that do not halt by inspecting them one by one and developing a specific algorithm for each one that determines if it halts or not.
Is impossible. You can’t, in general, inspect Turing machines one-by-one to determine if they halt.