How to Write CoffeeScript Efficiently

Re:How to Write CoffeeScript Efficiently by nilbus on Tuesday November 29, 2011 @08:25AM (#3290177)

Could someone explain how {@foo} = bar compiles into this.foo = bar.foo;?

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Re:How to Write CoffeeScript Efficiently by yesbabyyes on Tuesday November 29, 2011 @08:41AM (#3290230)

"@" is an alias for "this.", so "@foo" is the same as "this.foo".

{foo} = bar is using destructuring assignment, it means, take property "foo" of bar and put it in variable foo, so

    {foo} = bar

compiles to

    var foo = bar.foo;

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Re:How to Write CoffeeScript Efficiently by nilbus on Tuesday November 29, 2011 @08:57AM (#3290270)

Thanks! It was the destructuring part that I wasn't understanding right away.

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Re:How to Write CoffeeScript Efficiently by yesbabyyes on Tuesday November 29, 2011 @10:18AM (#3290607)

No problem! CoffeeScript's destructuring is really nice, IMO:

    [first, rest..., last] = someArray

    professions =
      programmer:
        studyTime: "5 years"
        salary: 10000
      salesman:
        studyTime: "2 years"
        salary: 15000
    
    {programmer: {salary}} = professions
    
    console.log "A programmer's salary is %s", salary

EDIT: Fixed bug, "developer" should be "programmer".

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Re:How to Write CoffeeScript Efficiently by jrnkntl on Tuesday November 29, 2011 @10:31AM (#3290682)

   {developer: {salary}} = professions

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