Python multi-level break and continue

Re:Python multi-level break and continue by eesmith on Tuesday September 06, 2022 @03:19PM (#32741930)

> The idea behind augmented assignment in Python is that it isn’t just an easier way to write the common practice of storing the result of a binary operation in its left-hand operand, but also a way for the left-hand operand in question to know that it should operate on itself, rather than creating a modified copy of itself.

Here's an example of how "a += b" is not syntactic sugar for "a = a + b". First, "a = a + b", which rebinds 'a' to a new object while leaving 'b' bound to the original:

  >>> a = b = [9,8]
  >>> a + b
  [9, 8, 9, 8]
  >>> a = a + b
  >>> a
  [9, 8, 9, 8]
  >>> b
  [9, 8]

Second, "a += b", which keeps both a and b bound to the same object:

  >>> a = b = [9,8]
  >>> a += b
  >>> a
  [9, 8, 9, 8]
  >>> b
  [9, 8, 9, 8]

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Re:Python multi-level break and continue by IshKebab on Thursday September 08, 2022 @02:31AM (#32761947)

Nah that's not a good enough example to motivate adding += to Python. You can just do `a.extend(b)`!

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Re:Python multi-level break and continue by eesmith on Thursday September 08, 2022 @04:12AM (#32762758)

It wasn't meant to be a convincing argument.

It was meant to show your comment at https://news.ycombinator.com/item?id=32741165 wasn't a relevant parallel, because it ignored how "a+=1" and "a=a+1" are different.

For a more convincing use, consider NumPy arrays, where a+=1 re-use the same (potentially very large) array, while a=a+1 creates a new array.

  import numpy
  a = b = numpy.array([[1,2], [3, 9]])
  a += 1  # modify in-place
  a = a + 1 # create a new array

  >>> a
  array([[ 3,  4],
         [ 5, 11]])

  >>> b
  array([[ 2,  3],
         [ 4, 10]])

In-place modification can improve performance over using intermediate/temporary arrays.

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