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A comment on Why do arrays start at 0?. Parent comment

Re:Why do arrays start at 0? by nicoburns on Wednesday August 24, 2022 @01:06PM (#32582455)
That's just convention though. There's no reason "[x]" couldn't have been defined to be "+ (x - 1) * sizeof". There would be no runtime cost to this, and the compile time penalty would be tiny even on ancient systems.
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Re:Why do arrays start at 0? by nwlieb on Wednesday August 24, 2022 @01:29PM (#32582780)
Is `(x - 1)` not a runtime cost if `x` is a runtime variable?
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Re:Why do arrays start at 0? by vikingerik on Wednesday August 24, 2022 @02:57PM (#32584103)
Not on many instruction architectures - addressing modes often support adding/subtracting a constant.
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