Re:Imaginary numbers are real
by yk on Saturday July 23, 2022 @03:07PM
(#32206534)
No, or at least not in a field. From the field axioms you can directly proof that 0x=(a-a)x = ax - ax =0, and therefore 0 doesn't have a well defined inverse. You can look at other algebraic structure, but those behave less like numbers.
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