True, but that doesn't matter at all given reasonable values of n. The number is in the range of n^2, but the algorithm is in the range O(1). Question is not that bad, my first thought was to use hash table to store what you see, then return when duplicate occurs. Don't like hash table fine, set an array of size n storing TRUE when you see the number. Notice it twice, then you've found the duplicate. No need for math, O(n) solution.

Honestly if you're stressing over a question like this, combined with thinking that integer overflow is even remotely something that you need to be concerned about in a question like this, you're definitely not passing any leetcode interview problems tossed around in today's interviewing culture.