Re:Volume of an n-ball
by thomasahle on Thursday May 12, 2022 @02:16AM
(#31349904)
Yes, this is a simple way to think about it:
If you choose n uniformly random values in [-1/2, 1/2] (the unit cube) then the sum of squares will be concentrated around n/12 (just take the variance).
This is way more than 1, which is what you would need to stay inside the unit ball.
If you choose n uniformly random values in [-1/2, 1/2] (the unit cube) then the sum of squares will be concentrated around n/12 (just take the variance).
This is way more than 1, which is what you would need to stay inside the unit ball.