Re:Go 1.18
by int_19h on Wednesday March 16, 2022 @06:16AM
(#30697063)
That's what I'm saying - any language with exceptions can be treated as if it was all Rust-style Result<T, E>, but with implicit ? after every expression. Well, and E is an open variant (like e.g. extensible variant types in OCaml), unless the language has checked exceptions like Java.
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