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Re:A pair of dice which never roll 7 (2004) by quacker on Sunday January 23, 2022 @01:40PM (#30048962)
My simple solution was:

- Use a normal d5 and d6.

- On a roll, if the sum on the dice face is >= 7, add 1 to the sum.

If I roll 2+3, the result is 5. If I roll 3+4, the sum is 7, so add 1 to get the result of 8.

The gives you this distribution, and is simple in practice.

      1  2  3  4  5
    1 2  3  4  5  6
    2 3  4  5  6  8
    3 4  5  6  8  9
    4 5  6  8  9  10
    5 6  8  9  10 11
    6 8  9  10 11 12

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