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Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by ben_w on Tuesday January 04, 2022 @06:00AM (#29793507)
It’s not a rational fraction, but I think it’s still a fraction. And now I’m wondering about 1/i, inverse quaternions (I barely get those even normally), and if 1/M ≠ M^(-1).

(Nice puns, BTW).

Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by hdjjhhvvhga on Tuesday January 04, 2022 @06:42AM (#29793774)
Of course these exist and that's why we have the process of rationalization.[0]

https://en.wikipedia.org/wiki/Rationalisation_(mathematics)

Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by caddybox on Tuesday January 04, 2022 @06:28AM (#29793689)
A rational number (with a terminating decimal representation or a repeating, non-terminating decimal representation) can always be expressed in fractional p/q form.

I don't think the additional "rational" qualifier is needed for fractions.

Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by ben_w on Tuesday January 04, 2022 @10:14AM (#29795600)
Looks like all three replies to this share the same misunderstanding of my intent, so I assume my use of “it’s” was unhelpfully vague.

1/pi is not rational and therefore not “a rational fraction”, but think 1/pi is “a fraction”.

Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by caddybox on Friday January 07, 2022 @08:12AM (#29838682)
Your comment brought me to the realization that the relationship doesn't hold both ways. A rational number can always be written as a fraction but a fraction is not always rational. Never considered this before today :)
Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by OJFord on Tuesday January 04, 2022 @06:06AM (#29793559)
A rational number is one that can be written as a fraction (of two integers).

What's a rational fraction? Integer parts as opposed to e.g. 1.5/2.3?

Re:Arm-Based 128-Core Ampere CPUs Cost a Fraction of x86 Price by samus on Tuesday January 04, 2022 @01:57PM (#29798537)
1/i = (1/i) * (i/i) = i/(i*i) = i/(-1) = -i