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A comment on Writing a self-modifying x86 factorial program. Parent comment

Re:Writing a self-modifying x86 factorial program by FastEatSlow on Wednesday December 15, 2021 @05:50AM (#29564216)
There was an edge case where when the input was 0x2, it returned 0x1, that was my quick way of handling that.
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Re:Writing a self-modifying x86 factorial program by unnouinceput on Wednesday December 15, 2021 @10:56AM (#29567730)
Let's see, step by step, if we put 2 in EAX what happens:

Init: EBX = 2; EAX = 2;

Loop: EBX = 1;//gets decremented

CMP EBX, 1;//it's 1 so we exit

Final result is 2. Sounds the edge case is not that of an edge after all

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