How does this work if the closure will mutate a closed-over location? e.g.

  (let ((x 1))
   (funcall (read (prin1-to-string (lambda () (setf x 3)))))
   (print x))

[edit]

Realized I have Emacs installed and tried it; the above prints "1" while calling the lambda without first serializing causes the (print x) to print "3"