Re:A mathematician's guided tour through higher dimensions
by zardo on Monday September 20, 2021 @09:11PM
(#28601007)
The car example works as a vector space, but not an inner-product space. There's no sensible way to rotate the length of the car to gasoline in the tank
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Re:A mathematician's guided tour through higher dimensions
by javajosh on Monday September 20, 2021 @10:30PM
(#28601450)
That's right! The less pithy answer: objects are the things that stay invariant under a transformation. In that sense then car length and gas are somehow MORE than linearly independent - they are "geometrically independent".
(Note there is a relationship between the length of the car and the gas tank when the car is moving fast (close to c) in your reference frame - but AFAIK there aren't any useful geometric transformations that depend on that fact. :)
Re:A mathematician's guided tour through higher dimensions
by zardo on Tuesday September 21, 2021 @01:20PM
(#28607300)
Linear independence doesn't guarantee that you can rotate, for that you need to know how to exchange one dimension for another.
Essentially you need to define a Pythagorean theorem for your space. You can do that for the car vector space, but there isn't a natural choice.
Re:A mathematician's guided tour through higher dimensions
by javajosh on Tuesday September 21, 2021 @03:28PM
(#28608863)
Isn't that the definition of rotation, the "exchanging one dimension for another"? In 2-D it keeps a point invariant, in 3-D a line, and in N-D it keeps the N-1 object invariant. (Side note: the more basic operation is reflection, since you can get rotation from two reflections)
Re:A mathematician's guided tour through higher dimensions
by zardo on Tuesday September 21, 2021 @05:07PM
(#28609971)
>Isn't that the definition of rotation, the "exchanging one dimension for another"?
Maybe? I think it allows solutions not typically considered to be rotations, like the special relativity example.