Perhaps one difference is that, while panics are always avoidable in a recovery function, stack overflows are not (if it happens to be deep enough already). Does the argument go “even a seemingly safe recovery function can’t be guaranteed to succeed, so prevent the illusion of safety”?
(To be clear: I’m not arguing, just trying to understand.)
In the absolute worst case scenario: stack unwinding is itself a piece of code[1]. In order to initiate the stack unwind, and deal with SEH/defer/dealloc, the Go runtime would need stack space to call that method. Someone might say, "freeze the stack and do the unwind on a different thread." The problem is the bit in the quotes is, again, at least one stack frame and needs stack space to execute.
I just checked the Go source, and it basically uses a linked list of stack frames in the heap[2]. If a stack is about to overflow, it allocates a new stack and continues in that stack. This does have a very minor performance penalty. So you're safe from this edge case :).
[1]: https://www.nongnu.org/libunwind/ [2]: https://golang.org/src/runtime/stack.go
Consider the following code:
The answer lies in trying to figure out how Go would successfully unwind that stack, it can't: when it calls `a` it will simply overflow again. Something that has been discussed is "StackAboutToOverflowException", but that only kicks the bucket down the road (unwinding could still cause an overflow).In truth, the problem exists because of implicit calls at the end of methods interacting with stack overflows, whether that's because of defer-like functionality, structured exception handling, or deconstructors.